Leaning on the GCF… (Trinomial Factoring)
In the 1st post of this series I made a case for teaching factoring. In the 2nd I described multiplying polynomials by “double distribution” (no FOIL!) so that:
So we do Greatest Common Factor work and arrive at 3 examples like these:
| ax + 5x | a@# + 5@# | a?%?%? + 5?%?%? |
| x(a + 5) | @#(a + 5) | ?%?%?(a + 5) |
Then this:
a(y + z) + 5(y + z)
(y + z)(a + 5)
(I use squiggles for the intermediate steps. Ach, this is nice. We compare it to our double distribution. But we need one more step back, first.)
an – 5n + ax – 5x
n(a – 5) + x(a – 5)
(a – 5)(n + x)
Now we see the double distribution, moving from bottom to top. Note, the first step is to factor out the GCF “pairwise,” which I emphasize orally and by underlining the pairs within the expression.
One day for just this, nothing harder than:
And trinomials come the next day (and in my next post)

I’m totally with you on this one.
what is the gcf of 6y,108?
6 no? is that some sort of trick question?