Puzzle – quick sum extension
December 9, 2007 am31 3:54 am
Using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9 exactly once each, the sum of any list of 1- and 2- digit numbers we create will be a multiple of 9. Several commenters demonstrated this convincingly here.
“Pseudonym” (probably not his real name), suggested several extensions, and I added a few of my own:
- What are the maximum and minimum sums, using only 1- and 2- digit numbers?
- Can every multiple of 9 between those 2 numbers be created?
- If we waive the limit on the number of digits in each addend, verify that all possible sums are still multiples of 9.
- Now, having waived the limits on the number of digits, what are the maximum and minimum sums?
- How many of the multiples of 9 between that max and that min can be created?
- Can we play the same set of games in base n, using the digits 0, 1, 2, … , n-2, n-1 ? Eg, in base 6, using the digits 0 through 5, can we make a list of one and two digit numbers that add to 100 (base 6) ?
Submit comments by clicking “comments,” above, but if you want to submit answers, click right here –> “Answers.”
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